Base | Representation |
---|---|
bin | 111011010010011000111… |
… | …0100011111101111011001 |
3 | 1001211222102020002202111221 |
4 | 1312210301310133233121 |
5 | 2032000400013234333 |
6 | 25155152415052041 |
7 | 1500462446024551 |
oct | 166446164375731 |
9 | 31758366082457 |
10 | 8148388805593 |
11 | 2661792064163 |
12 | ab7266b11021 |
13 | 47150b41b43a |
14 | 202554064161 |
15 | e1e59383d2d |
hex | 76931d1fbd9 |
8148388805593 has 2 divisors, whose sum is σ = 8148388805594. Its totient is φ = 8148388805592.
The previous prime is 8148388805573. The next prime is 8148388805647. The reversal of 8148388805593 is 3955088838418.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5162947372944 + 2985441432649 = 2272212^2 + 1727843^2 .
It is a cyclic number.
It is not a de Polignac number, because 8148388805593 - 237 = 8010949852121 is a prime.
It is a super-2 number, since 2×81483888055932 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (8148388805573) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4074194402796 + 4074194402797.
It is an arithmetic number, because the mean of its divisors is an integer number (4074194402797).
Almost surely, 28148388805593 is an apocalyptic number.
It is an amenable number.
8148388805593 is a deficient number, since it is larger than the sum of its proper divisors (1).
8148388805593 is an equidigital number, since it uses as much as digits as its factorization.
8148388805593 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 265420800, while the sum is 70.
The spelling of 8148388805593 in words is "eight trillion, one hundred forty-eight billion, three hundred eighty-eight million, eight hundred five thousand, five hundred ninety-three".
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