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8148388805593 is a prime number
BaseRepresentation
bin111011010010011000111…
…0100011111101111011001
31001211222102020002202111221
41312210301310133233121
52032000400013234333
625155152415052041
71500462446024551
oct166446164375731
931758366082457
108148388805593
112661792064163
12ab7266b11021
1347150b41b43a
14202554064161
15e1e59383d2d
hex76931d1fbd9

8148388805593 has 2 divisors, whose sum is σ = 8148388805594. Its totient is φ = 8148388805592.

The previous prime is 8148388805573. The next prime is 8148388805647. The reversal of 8148388805593 is 3955088838418.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5162947372944 + 2985441432649 = 2272212^2 + 1727843^2 .

It is a cyclic number.

It is not a de Polignac number, because 8148388805593 - 237 = 8010949852121 is a prime.

It is a super-2 number, since 2×81483888055932 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (8148388805573) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4074194402796 + 4074194402797.

It is an arithmetic number, because the mean of its divisors is an integer number (4074194402797).

Almost surely, 28148388805593 is an apocalyptic number.

It is an amenable number.

8148388805593 is a deficient number, since it is larger than the sum of its proper divisors (1).

8148388805593 is an equidigital number, since it uses as much as digits as its factorization.

8148388805593 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 265420800, while the sum is 70.

The spelling of 8148388805593 in words is "eight trillion, one hundred forty-eight billion, three hundred eighty-eight million, eight hundred five thousand, five hundred ninety-three".