Base | Representation |
---|---|
bin | 100101111100011011… |
… | …0111001010010111001 |
3 | 21210022210120002121102 |
4 | 1023320312321102321 |
5 | 2313340021120403 |
6 | 101233344421145 |
7 | 5613156154442 |
oct | 1137066712271 |
9 | 253283502542 |
10 | 81484551353 |
11 | 316149a5527 |
12 | 139610177b5 |
13 | 78b787847a |
14 | 3d2ddba2c9 |
15 | 21bd9b5b88 |
hex | 12f8db94b9 |
81484551353 has 2 divisors, whose sum is σ = 81484551354. Its totient is φ = 81484551352.
The previous prime is 81484551329. The next prime is 81484551359. The reversal of 81484551353 is 35315548418.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 67979089984 + 13505461369 = 260728^2 + 116213^2 .
It is a cyclic number.
It is not a de Polignac number, because 81484551353 - 26 = 81484551289 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 81484551298 and 81484551307.
It is not a weakly prime, because it can be changed into another prime (81484551359) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40742275676 + 40742275677.
It is an arithmetic number, because the mean of its divisors is an integer number (40742275677).
Almost surely, 281484551353 is an apocalyptic number.
It is an amenable number.
81484551353 is a deficient number, since it is larger than the sum of its proper divisors (1).
81484551353 is an equidigital number, since it uses as much as digits as its factorization.
81484551353 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1152000, while the sum is 47.
The spelling of 81484551353 in words is "eighty-one billion, four hundred eighty-four million, five hundred fifty-one thousand, three hundred fifty-three".
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