Base | Representation |
---|---|
bin | 10111111001101000100… |
… | …00011100100101010011 |
3 | 2220111200220210210112121 |
4 | 23330310100130211103 |
5 | 101423322130331042 |
6 | 1425132225435111 |
7 | 113221325256556 |
oct | 13746420344523 |
9 | 2814626723477 |
10 | 821215480147 |
11 | 297303802a67 |
12 | 1131a749ba97 |
13 | 5c59540881a |
14 | 2ba65c4a69d |
15 | 16565b05367 |
hex | bf3441c953 |
821215480147 has 2 divisors, whose sum is σ = 821215480148. Its totient is φ = 821215480146.
The previous prime is 821215480097. The next prime is 821215480159. The reversal of 821215480147 is 741084512128.
821215480147 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 821215480147 - 235 = 786855741779 is a prime.
It is a super-2 number, since 2×8212154801472 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (821215480247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 410607740073 + 410607740074.
It is an arithmetic number, because the mean of its divisors is an integer number (410607740074).
Almost surely, 2821215480147 is an apocalyptic number.
821215480147 is a deficient number, since it is larger than the sum of its proper divisors (1).
821215480147 is an equidigital number, since it uses as much as digits as its factorization.
821215480147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 143360, while the sum is 43.
The spelling of 821215480147 in words is "eight hundred twenty-one billion, two hundred fifteen million, four hundred eighty thousand, one hundred forty-seven".
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