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83123536418393 is a prime number
BaseRepresentation
bin10010111001100110110100…
…110111000101011001011001
3101220022112101011200120121112
4102321212310313011121121
541343344000310342033
6452442231522150105
723336322502446512
oct2271466467053131
9356275334616545
1083123536418393
1124538548311469
1293a5a941b2335
13374c692427333
1416752b4751a09
15992379835c48
hex4b99b4dc5659

83123536418393 has 2 divisors, whose sum is σ = 83123536418394. Its totient is φ = 83123536418392.

The previous prime is 83123536418387. The next prime is 83123536418557. The reversal of 83123536418393 is 39381463532138.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 80649685587289 + 2473850831104 = 8980517^2 + 1572848^2 .

It is a cyclic number.

It is not a de Polignac number, because 83123536418393 - 212 = 83123536414297 is a prime.

It is a super-3 number, since 3×831235364183933 (a number of 43 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (83123536418303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 41561768209196 + 41561768209197.

It is an arithmetic number, because the mean of its divisors is an integer number (41561768209197).

Almost surely, 283123536418393 is an apocalyptic number.

It is an amenable number.

83123536418393 is a deficient number, since it is larger than the sum of its proper divisors (1).

83123536418393 is an equidigital number, since it uses as much as digits as its factorization.

83123536418393 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 33592320, while the sum is 59.

The spelling of 83123536418393 in words is "eighty-three trillion, one hundred twenty-three billion, five hundred thirty-six million, four hundred eighteen thousand, three hundred ninety-three".