Base | Representation |
---|---|
bin | 10010111001100110111011… |
… | …000110001101100100111001 |
3 | 101220022112122110120021120012 |
4 | 102321212323012031210321 |
5 | 41343344204102003403 |
6 | 452442250140511305 |
7 | 23336325213001304 |
oct | 2271467306154471 |
9 | 356275573507505 |
10 | 83123641047353 |
11 | 245385a1384785 |
12 | 93a5b0324b535 |
13 | 374c6aaccba6a |
14 | 16752c45c9b3b |
15 | 992383b01ed8 |
hex | 4b99bb18d939 |
83123641047353 has 2 divisors, whose sum is σ = 83123641047354. Its totient is φ = 83123641047352.
The previous prime is 83123641047301. The next prime is 83123641047373. The reversal of 83123641047353 is 35374014632138.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 55541366001664 + 27582275045689 = 7452608^2 + 5251883^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-83123641047353 is a prime.
It is not a weakly prime, because it can be changed into another prime (83123641047373) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 41561820523676 + 41561820523677.
It is an arithmetic number, because the mean of its divisors is an integer number (41561820523677).
Almost surely, 283123641047353 is an apocalyptic number.
It is an amenable number.
83123641047353 is a deficient number, since it is larger than the sum of its proper divisors (1).
83123641047353 is an equidigital number, since it uses as much as digits as its factorization.
83123641047353 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4354560, while the sum is 50.
The spelling of 83123641047353 in words is "eighty-three trillion, one hundred twenty-three billion, six hundred forty-one million, forty-seven thousand, three hundred fifty-three".
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