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83123872301881 is a prime number
BaseRepresentation
bin10010111001100111001000…
…111000011000001100111001
3101220022120020120201020010201
4102321213020320120030321
541343400142302130011
6452442325121242201
723336334021430615
oct2271471070301471
9356276216636121
1083123872301881
11245386aa974724
1293a5b68793361
13374c716baa068
1416753071c6345
15992399081cc1
hex4b99c8e18339

83123872301881 has 2 divisors, whose sum is σ = 83123872301882. Its totient is φ = 83123872301880.

The previous prime is 83123872301851. The next prime is 83123872301891. The reversal of 83123872301881 is 18810327832138.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 77034131594281 + 6089740707600 = 8776909^2 + 2467740^2 .

It is a cyclic number.

It is not a de Polignac number, because 83123872301881 - 25 = 83123872301849 is a prime.

It is a super-2 number, since 2×831238723018812 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (83123872301851) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 41561936150940 + 41561936150941.

It is an arithmetic number, because the mean of its divisors is an integer number (41561936150941).

Almost surely, 283123872301881 is an apocalyptic number.

It is an amenable number.

83123872301881 is a deficient number, since it is larger than the sum of its proper divisors (1).

83123872301881 is an equidigital number, since it uses as much as digits as its factorization.

83123872301881 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3096576, while the sum is 55.

The spelling of 83123872301881 in words is "eighty-three trillion, one hundred twenty-three billion, eight hundred seventy-two million, three hundred one thousand, eight hundred eighty-one".