Base | Representation |
---|---|
bin | 10010111001100111011101… |
… | …000110000111011010111011 |
3 | 101220022121010012212121102221 |
4 | 102321213131012013122323 |
5 | 41343401341112304413 |
6 | 452442422514304511 |
7 | 23336345310216403 |
oct | 2271473506073273 |
9 | 356277105777387 |
10 | 83124211447483 |
11 | 24538864355848 |
12 | 93a6042288137 |
13 | 374c76c23282b |
14 | 167533a269803 |
15 | 9923b8c2468d |
hex | 4b99dd1876bb |
83124211447483 has 2 divisors, whose sum is σ = 83124211447484. Its totient is φ = 83124211447482.
The previous prime is 83124211447379. The next prime is 83124211447489. The reversal of 83124211447483 is 38474411242138.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-83124211447483 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 83124211447483.
It is not a weakly prime, because it can be changed into another prime (83124211447489) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 41562105723741 + 41562105723742.
It is an arithmetic number, because the mean of its divisors is an integer number (41562105723742).
Almost surely, 283124211447483 is an apocalyptic number.
83124211447483 is a deficient number, since it is larger than the sum of its proper divisors (1).
83124211447483 is an equidigital number, since it uses as much as digits as its factorization.
83124211447483 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 4128768, while the sum is 52.
The spelling of 83124211447483 in words is "eighty-three trillion, one hundred twenty-four billion, two hundred eleven million, four hundred forty-seven thousand, four hundred eighty-three".
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