Base | Representation |
---|---|
bin | 11000001101001011110… |
… | …01101100110000110011 |
3 | 2221111210102222000101010 |
4 | 30012211321230300303 |
5 | 102111321241214243 |
6 | 1434025551442003 |
7 | 114042412546623 |
oct | 14064571546063 |
9 | 2844712860333 |
10 | 831712054323 |
11 | 2a07aa854557 |
12 | 115236826303 |
13 | 60578c4b967 |
14 | 2c37dd12883 |
15 | 1697c3a1433 |
hex | c1a5e6cc33 |
831712054323 has 4 divisors (see below), whose sum is σ = 1108949405768. Its totient is φ = 554474702880.
The previous prime is 831712054307. The next prime is 831712054351. The reversal of 831712054323 is 323450217138.
831712054323 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 831712054323 - 24 = 831712054307 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (831712054373) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 138618675718 + ... + 138618675723.
It is an arithmetic number, because the mean of its divisors is an integer number (277237351442).
Almost surely, 2831712054323 is an apocalyptic number.
831712054323 is a deficient number, since it is larger than the sum of its proper divisors (277237351445).
831712054323 is a wasteful number, since it uses less digits than its factorization.
831712054323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 277237351444.
The product of its (nonzero) digits is 120960, while the sum is 39.
The spelling of 831712054323 in words is "eight hundred thirty-one billion, seven hundred twelve million, fifty-four thousand, three hundred twenty-three".
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