Base | Representation |
---|---|
bin | 100110110101100001… |
… | …1100000001010000001 |
3 | 21222021022200021122111 |
4 | 1031223003200022001 |
5 | 2331301004141011 |
6 | 102151425135321 |
7 | 6011512126615 |
oct | 1155303401201 |
9 | 258238607574 |
10 | 83400458881 |
11 | 32408426183 |
12 | 141b678a541 |
13 | 7b3178b76c |
14 | 4072625345 |
15 | 2281cb7121 |
hex | 136b0e0281 |
83400458881 has 2 divisors, whose sum is σ = 83400458882. Its totient is φ = 83400458880.
The previous prime is 83400458863. The next prime is 83400458957. The reversal of 83400458881 is 18885400438.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 46919458881 + 36481000000 = 216609^2 + 191000^2 .
It is a cyclic number.
It is not a de Polignac number, because 83400458881 - 25 = 83400458849 is a prime.
It is a super-2 number, since 2×834004588812 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (83460458881) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 41700229440 + 41700229441.
It is an arithmetic number, because the mean of its divisors is an integer number (41700229441).
Almost surely, 283400458881 is an apocalyptic number.
It is an amenable number.
83400458881 is a deficient number, since it is larger than the sum of its proper divisors (1).
83400458881 is an equidigital number, since it uses as much as digits as its factorization.
83400458881 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 983040, while the sum is 49.
The spelling of 83400458881 in words is "eighty-three billion, four hundred million, four hundred fifty-eight thousand, eight hundred eighty-one".
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