Base | Representation |
---|---|
bin | 100110110110000001… |
… | …0000010001000000011 |
3 | 21222022110112002100001 |
4 | 1031230002002020003 |
5 | 2331314203212242 |
6 | 102153212340431 |
7 | 6012101351113 |
oct | 1155402021003 |
9 | 258273462301 |
10 | 83416850947 |
11 | 32416701841 |
12 | 14200174717 |
13 | 7b34caa901 |
14 | 4074891043 |
15 | 2283453eb7 |
hex | 136c082203 |
83416850947 has 2 divisors, whose sum is σ = 83416850948. Its totient is φ = 83416850946.
The previous prime is 83416850879. The next prime is 83416850969. The reversal of 83416850947 is 74905861438.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-83416850947 is a prime.
It is not a weakly prime, because it can be changed into another prime (83416850977) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 41708425473 + 41708425474.
It is an arithmetic number, because the mean of its divisors is an integer number (41708425474).
Almost surely, 283416850947 is an apocalyptic number.
83416850947 is a deficient number, since it is larger than the sum of its proper divisors (1).
83416850947 is an equidigital number, since it uses as much as digits as its factorization.
83416850947 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5806080, while the sum is 55.
It can be divided in two parts, 834168 and 50947, that added together give a triangular number (885115 = T1330).
The spelling of 83416850947 in words is "eighty-three billion, four hundred sixteen million, eight hundred fifty thousand, nine hundred forty-seven".
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