Base | Representation |
---|---|
bin | 10011000001010000001001… |
… | …100011101101001110100011 |
3 | 101222011202112200122022010010 |
4 | 103001100021203231032203 |
5 | 41431001014003142011 |
6 | 453523443305340003 |
7 | 23422302540301206 |
oct | 2301201143551643 |
9 | 358152480568103 |
10 | 83648943412131 |
11 | 24720354918349 |
12 | 946b885a97603 |
13 | 378a0a51cb2c6 |
14 | 16928b7dc393d |
15 | 9a0d7ac321a6 |
hex | 4c14098ed3a3 |
83648943412131 has 4 divisors (see below), whose sum is σ = 111531924549512. Its totient is φ = 55765962274752.
The previous prime is 83648943412129. The next prime is 83648943412147. The reversal of 83648943412131 is 13121434984638.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 83648943412131 - 21 = 83648943412129 is a prime.
It is a super-2 number, since 2×836489434121312 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (83648943419131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13941490568686 + ... + 13941490568691.
It is an arithmetic number, because the mean of its divisors is an integer number (27882981137378).
Almost surely, 283648943412131 is an apocalyptic number.
83648943412131 is a deficient number, since it is larger than the sum of its proper divisors (27882981137381).
83648943412131 is a wasteful number, since it uses less digits than its factorization.
83648943412131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 27882981137380.
The product of its digits is 11943936, while the sum is 57.
The spelling of 83648943412131 in words is "eighty-three trillion, six hundred forty-eight billion, nine hundred forty-three million, four hundred twelve thousand, one hundred thirty-one".
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