Base | Representation |
---|---|
bin | 100111001010111000… |
… | …0111001000001000001 |
3 | 22001010020222100121222 |
4 | 1032111300321001001 |
5 | 2334232423002012 |
6 | 102350503124425 |
7 | 6035332463543 |
oct | 1162560710101 |
9 | 261106870558 |
10 | 84117000257 |
11 | 32745943334 |
12 | 14376743715 |
13 | 7c1706cc44 |
14 | 40dd867693 |
15 | 22c4b55972 |
hex | 1395c39041 |
84117000257 has 2 divisors, whose sum is σ = 84117000258. Its totient is φ = 84117000256.
The previous prime is 84117000199. The next prime is 84117000283. The reversal of 84117000257 is 75200071148.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 61202306881 + 22914693376 = 247391^2 + 151376^2 .
It is a cyclic number.
It is not a de Polignac number, because 84117000257 - 28 = 84117000001 is a prime.
It is a super-2 number, since 2×841170002572 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (84117000857) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 42058500128 + 42058500129.
It is an arithmetic number, because the mean of its divisors is an integer number (42058500129).
Almost surely, 284117000257 is an apocalyptic number.
It is an amenable number.
84117000257 is a deficient number, since it is larger than the sum of its proper divisors (1).
84117000257 is an equidigital number, since it uses as much as digits as its factorization.
84117000257 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15680, while the sum is 35.
The spelling of 84117000257 in words is "eighty-four billion, one hundred seventeen million, two hundred fifty-seven", and thus it is an aban number.
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