Base | Representation |
---|---|
bin | 100111101111001110… |
… | …0111100101000011001 |
3 | 22011021020200211001201 |
4 | 1033132130330220121 |
5 | 2344232121241303 |
6 | 103111505314201 |
7 | 6110501233513 |
oct | 1173634745031 |
9 | 264236624051 |
10 | 85336508953 |
11 | 33211264263 |
12 | 14657035961 |
13 | 807c905017 |
14 | 41b77d4bb3 |
15 | 2346c4681d |
hex | 13de73ca19 |
85336508953 has 2 divisors, whose sum is σ = 85336508954. Its totient is φ = 85336508952.
The previous prime is 85336508923. The next prime is 85336509079. The reversal of 85336508953 is 35980563358.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 74056369689 + 11280139264 = 272133^2 + 106208^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-85336508953 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 85336508894 and 85336508903.
It is not a weakly prime, because it can be changed into another prime (85336508923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 42668254476 + 42668254477.
It is an arithmetic number, because the mean of its divisors is an integer number (42668254477).
Almost surely, 285336508953 is an apocalyptic number.
It is an amenable number.
85336508953 is a deficient number, since it is larger than the sum of its proper divisors (1).
85336508953 is an equidigital number, since it uses as much as digits as its factorization.
85336508953 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11664000, while the sum is 55.
The spelling of 85336508953 in words is "eighty-five billion, three hundred thirty-six million, five hundred eight thousand, nine hundred fifty-three".
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