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85336508953 is a prime number
BaseRepresentation
bin100111101111001110…
…0111100101000011001
322011021020200211001201
41033132130330220121
52344232121241303
6103111505314201
76110501233513
oct1173634745031
9264236624051
1085336508953
1133211264263
1214657035961
13807c905017
1441b77d4bb3
152346c4681d
hex13de73ca19

85336508953 has 2 divisors, whose sum is σ = 85336508954. Its totient is φ = 85336508952.

The previous prime is 85336508923. The next prime is 85336509079. The reversal of 85336508953 is 35980563358.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 74056369689 + 11280139264 = 272133^2 + 106208^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-85336508953 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 85336508894 and 85336508903.

It is not a weakly prime, because it can be changed into another prime (85336508923) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 42668254476 + 42668254477.

It is an arithmetic number, because the mean of its divisors is an integer number (42668254477).

Almost surely, 285336508953 is an apocalyptic number.

It is an amenable number.

85336508953 is a deficient number, since it is larger than the sum of its proper divisors (1).

85336508953 is an equidigital number, since it uses as much as digits as its factorization.

85336508953 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11664000, while the sum is 55.

The spelling of 85336508953 in words is "eighty-five billion, three hundred thirty-six million, five hundred eight thousand, nine hundred fifty-three".