Base | Representation |
---|---|
bin | 10011011001111001001101… |
… | …110111001000111101100111 |
3 | 102012011122102001222121202121 |
4 | 103121321031313020331213 |
5 | 42141222020424044113 |
6 | 501301414144450411 |
7 | 23655530624643364 |
oct | 2331711567107547 |
9 | 365148361877677 |
10 | 85342306471783 |
11 | 25213518152369 |
12 | 96a3ab1919a07 |
13 | 388098b90742a |
14 | 17108380c146b |
15 | 9cee38a4ee8d |
hex | 4d9e4ddc8f67 |
85342306471783 has 16 divisors (see below), whose sum is σ = 87197398718976. Its totient is φ = 83507257258560.
The previous prime is 85342306471777. The next prime is 85342306471811. The reversal of 85342306471783 is 38717460324358.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-85342306471783 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (85342306471483) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 38358610 + ... + 40522432.
It is an arithmetic number, because the mean of its divisors is an integer number (5449837419936).
Almost surely, 285342306471783 is an apocalyptic number.
85342306471783 is a gapful number since it is divisible by the number (83) formed by its first and last digit.
85342306471783 is a deficient number, since it is larger than the sum of its proper divisors (1855092247193).
85342306471783 is a wasteful number, since it uses less digits than its factorization.
85342306471783 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2168454.
The product of its (nonzero) digits is 81285120, while the sum is 61.
The spelling of 85342306471783 in words is "eighty-five trillion, three hundred forty-two billion, three hundred six million, four hundred seventy-one thousand, seven hundred eighty-three".
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