Base | Representation |
---|---|
bin | 101000011101110010… |
… | …1110100110101111001 |
3 | 22022022011000112220212 |
4 | 1100323211310311321 |
5 | 2410432133224213 |
6 | 103530525400505 |
7 | 6164304211412 |
oct | 1207345646571 |
9 | 268264015825 |
10 | 86899117433 |
11 | 33943317127 |
12 | 14a12409135 |
13 | 826b57861b |
14 | 42c5154809 |
15 | 23d900b9a8 |
hex | 143b974d79 |
86899117433 has 2 divisors, whose sum is σ = 86899117434. Its totient is φ = 86899117432.
The previous prime is 86899117411. The next prime is 86899117453. The reversal of 86899117433 is 33471199868.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 84301380409 + 2597737024 = 290347^2 + 50968^2 .
It is a cyclic number.
It is not a de Polignac number, because 86899117433 - 214 = 86899101049 is a prime.
It is a super-2 number, since 2×868991174332 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (86899117453) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 43449558716 + 43449558717.
It is an arithmetic number, because the mean of its divisors is an integer number (43449558717).
Almost surely, 286899117433 is an apocalyptic number.
It is an amenable number.
86899117433 is a deficient number, since it is larger than the sum of its proper divisors (1).
86899117433 is an equidigital number, since it uses as much as digits as its factorization.
86899117433 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 7838208, while the sum is 59.
The spelling of 86899117433 in words is "eighty-six billion, eight hundred ninety-nine million, one hundred seventeen thousand, four hundred thirty-three".
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