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89481515924113 is a prime number
BaseRepresentation
bin10100010110001000001001…
…111110000111101010010001
3102201211100102200211012220121
4110112020021332013222101
543212031121034032423
6514151124012310241
724563553244531225
oct2426101176075221
9381740380735817
1089481515924113
1126569996a62995
12a05214a772381
133ac10bc571461
141814cdda64785
15a5294612045d
hex516209f87a91

89481515924113 has 2 divisors, whose sum is σ = 89481515924114. Its totient is φ = 89481515924112.

The previous prime is 89481515924083. The next prime is 89481515924123. The reversal of 89481515924113 is 31142951518498.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 60505871216704 + 28975644707409 = 7778552^2 + 5382903^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-89481515924113 is a prime.

It is a super-4 number, since 4×894815159241134 (a number of 57 digits) contains 4444 as substring.

It is not a weakly prime, because it can be changed into another prime (89481515924123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 44740757962056 + 44740757962057.

It is an arithmetic number, because the mean of its divisors is an integer number (44740757962057).

Almost surely, 289481515924113 is an apocalyptic number.

It is an amenable number.

89481515924113 is a deficient number, since it is larger than the sum of its proper divisors (1).

89481515924113 is an equidigital number, since it uses as much as digits as its factorization.

89481515924113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 12441600, while the sum is 61.

The spelling of 89481515924113 in words is "eighty-nine trillion, four hundred eighty-one billion, five hundred fifteen million, nine hundred twenty-four thousand, one hundred thirteen".