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89594000113 is a prime number
BaseRepresentation
bin101001101110000110…
…1111111001011110001
322120020221220202222111
41103130031333023301
52431442031000423
6105054154205321
76321136302262
oct1233415771361
9276227822874
1089594000113
1134aa65283a2
1215444a23841
1385aa98ca67
14449d014969
1524e58d060d
hex14dc37f2f1

89594000113 has 2 divisors, whose sum is σ = 89594000114. Its totient is φ = 89594000112.

The previous prime is 89594000063. The next prime is 89594000123. The reversal of 89594000113 is 31100049598.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 59076705249 + 30517294864 = 243057^2 + 174692^2 .

It is a cyclic number.

It is not a de Polignac number, because 89594000113 - 217 = 89593869041 is a prime.

It is not a weakly prime, because it can be changed into another prime (89594000123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 44797000056 + 44797000057.

It is an arithmetic number, because the mean of its divisors is an integer number (44797000057).

Almost surely, 289594000113 is an apocalyptic number.

It is an amenable number.

89594000113 is a deficient number, since it is larger than the sum of its proper divisors (1).

89594000113 is an equidigital number, since it uses as much as digits as its factorization.

89594000113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 38880, while the sum is 40.

The spelling of 89594000113 in words is "eighty-nine billion, five hundred ninety-four million, one hundred thirteen", and thus it is an aban number.