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9125497 is a prime number
BaseRepresentation
bin100010110011…
…111001111001
3122011121211101
4202303321321
54314003442
6523331401
7140364643
oct42637171
918147741
109125497
115173137
123080b61
131b76804
1412d7893
15c03cb7
hex8b3e79

9125497 has 2 divisors, whose sum is σ = 9125498. Its totient is φ = 9125496.

The previous prime is 9125483. The next prime is 9125507. The reversal of 9125497 is 7945219.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9096256 + 29241 = 3016^2 + 171^2 .

It is an emirp because it is prime and its reverse (7945219) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 9125497 - 219 = 8601209 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (9125197) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4562748 + 4562749.

It is an arithmetic number, because the mean of its divisors is an integer number (4562749).

Almost surely, 29125497 is an apocalyptic number.

It is an amenable number.

9125497 is a deficient number, since it is larger than the sum of its proper divisors (1).

9125497 is an equidigital number, since it uses as much as digits as its factorization.

9125497 is an evil number, because the sum of its binary digits is even.

The product of its digits is 22680, while the sum is 37.

The square root of 9125497 is about 3020.8437563039. The cubic root of 9125497 is about 208.9707535978.

The spelling of 9125497 in words is "nine million, one hundred twenty-five thousand, four hundred ninety-seven".