9128402039113 has 4 divisors (see below), whose sum is σ = 10432459473280. Its totient is φ = 7824344604948.

The previous prime is 9128402039101. The next prime is 9128402039123. The reversal of 9128402039113 is 3119302048219.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 9128402039113 - 2¹³ = 9128402030921 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 9128402039113.

It is not an unprimeable number, because it can be changed into a prime (9128402039123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 652028717073 + ... + 652028717086.

It is an arithmetic number, because the mean of its divisors is an integer number (2608114868320).

Almost surely, 2^{9128402039113} is an apocalyptic number.

It is an amenable number.

9128402039113 is a deficient number, since it is larger than the sum of its proper divisors (1304057434167).

9128402039113 is a wasteful number, since it uses less digits than its factorization.

9128402039113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1304057434166.

The product of its (nonzero) digits is 93312, while the sum is 43.

The spelling of 9128402039113 in words is "nine trillion, one hundred twenty-eight billion, four hundred two million, thirty-nine thousand, one hundred thirteen".