Base | Representation |
---|---|
bin | 110110011011010… |
… | …110110010010001 |
3 | 2100122020100210122 |
4 | 312123112302101 |
5 | 3332231002011 |
6 | 230335440025 |
7 | 31425366212 |
oct | 6633266221 |
9 | 2318210718 |
10 | 913140881 |
11 | 429498294 |
12 | 215986015 |
13 | 117247a63 |
14 | 893bb409 |
15 | 552753db |
hex | 366d6c91 |
913140881 has 2 divisors, whose sum is σ = 913140882. Its totient is φ = 913140880.
The previous prime is 913140821. The next prime is 913140913. The reversal of 913140881 is 188041319.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 488410000 + 424730881 = 22100^2 + 20609^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-913140881 is a prime.
It is a super-2 number, since 2×9131408812 = 1667652537106912322, which contains 22 as substring.
It is a Chen prime.
It is equal to p46647080 and since 913140881 and 46647080 have the same sum of digits, it is a Honaker prime.
It is not a weakly prime, because it can be changed into another prime (913140821) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 456570440 + 456570441.
It is an arithmetic number, because the mean of its divisors is an integer number (456570441).
Almost surely, 2913140881 is an apocalyptic number.
It is an amenable number.
913140881 is a deficient number, since it is larger than the sum of its proper divisors (1).
913140881 is an equidigital number, since it uses as much as digits as its factorization.
913140881 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 35.
The square root of 913140881 is about 30218.2210098477. The cubic root of 913140881 is about 970.1657282282.
The spelling of 913140881 in words is "nine hundred thirteen million, one hundred forty thousand, eight hundred eighty-one".
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