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91322050081 = 694731314497
BaseRepresentation
bin101010100001100110…
…1111110011000100001
322201201101112210220011
41111003031332120201
52444011421100311
6105541444244521
76412021421653
oct1250315763041
9281641483804
1091322050081
1135802a09969
12158476a0741
1387c49aa832
1445c471c6d3
152597475321
hex154337e621

91322050081 has 4 divisors (see below), whose sum is σ = 91323434052. Its totient is φ = 91320666112.

The previous prime is 91322050069. The next prime is 91322050103. The reversal of 91322050081 is 18005022319.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 23401350625 + 67920699456 = 152975^2 + 260616^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-91322050081 is a prime.

It is a super-2 number, since 2×913220500812 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (91322050031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 587776 + ... + 726721.

It is an arithmetic number, because the mean of its divisors is an integer number (22830858513).

Almost surely, 291322050081 is an apocalyptic number.

It is an amenable number.

91322050081 is a deficient number, since it is larger than the sum of its proper divisors (1383971).

91322050081 is a wasteful number, since it uses less digits than its factorization.

91322050081 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1383970.

The product of its (nonzero) digits is 4320, while the sum is 31.

The spelling of 91322050081 in words is "ninety-one billion, three hundred twenty-two million, fifty thousand, eighty-one".

Divisors: 1 69473 1314497 91322050081