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913500097441 = 59138111211479
BaseRepresentation
bin11010100101100001101…
…10010100101110100001
310020022220101121002102021
431102300312110232201
5104431322011104231
61535353421221441
7122666245466131
oct15226066245641
93208811532367
10913500097441
1132245aa98918
12129061401881
13681b1648349
14322dc330ac1
1518b67815811
hexd4b0d94ba1

913500097441 has 8 divisors (see below), whose sum is σ = 929655921600. Its totient is φ = 897366699120.

The previous prime is 913500097427. The next prime is 913500097507. The reversal of 913500097441 is 144790005319.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 913500097441 - 25 = 913500097409 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (913507097441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5524261 + ... + 5687218.

It is an arithmetic number, because the mean of its divisors is an integer number (116206990200).

Almost surely, 2913500097441 is an apocalyptic number.

It is an amenable number.

913500097441 is a deficient number, since it is larger than the sum of its proper divisors (16155824159).

913500097441 is a wasteful number, since it uses less digits than its factorization.

913500097441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11212919.

The product of its (nonzero) digits is 136080, while the sum is 43.

The spelling of 913500097441 in words is "nine hundred thirteen billion, five hundred million, ninety-seven thousand, four hundred forty-one".

Divisors: 1 59 1381 81479 11211479 661477261 15483052499 913500097441