Base | Representation |
---|---|
bin | 10100110010000110100111… |
… | …101100100101110011110011 |
3 | 102222122010201210022201111101 |
4 | 110302012213230211303303 |
5 | 43440030404200313301 |
6 | 522222231302225231 |
7 | 25152502432065124 |
oct | 2462064754456363 |
9 | 388563653281441 |
10 | 91404012510451 |
11 | 27140251189993 |
12 | a302862a25217 |
13 | 3c00490ca6434 |
14 | 187dd9917c04b |
15 | a87964dd3701 |
hex | 5321a7b25cf3 |
91404012510451 has 2 divisors, whose sum is σ = 91404012510452. Its totient is φ = 91404012510450.
The previous prime is 91404012510427. The next prime is 91404012510457. The reversal of 91404012510451 is 15401521040419.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 91404012510451 - 27 = 91404012510323 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 91404012510451.
It is not a weakly prime, because it can be changed into another prime (91404012510457) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 45702006255225 + 45702006255226.
It is an arithmetic number, because the mean of its divisors is an integer number (45702006255226).
Almost surely, 291404012510451 is an apocalyptic number.
91404012510451 is a deficient number, since it is larger than the sum of its proper divisors (1).
91404012510451 is an equidigital number, since it uses as much as digits as its factorization.
91404012510451 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 28800, while the sum is 37.
The spelling of 91404012510451 in words is "ninety-one trillion, four hundred four billion, twelve million, five hundred ten thousand, four hundred fifty-one".
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