Search a number
-
+
92734805113 is a prime number
BaseRepresentation
bin101011001011101101…
…1001101010001111001
322212100211220012110121
41112113123031101321
53004410102230423
6110333552413241
76462024560206
oct1262733152171
9285324805417
1092734805113
113636841a705
1215b80847221
13898b5a3b62
1446ba1d0cad
15262b4d945d
hex15976cd479

92734805113 has 2 divisors, whose sum is σ = 92734805114. Its totient is φ = 92734805112.

The previous prime is 92734805041. The next prime is 92734805131. The reversal of 92734805113 is 31150843729.

Together with next prime (92734805131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 79539228729 + 13195576384 = 282027^2 + 114872^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-92734805113 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 92734805113.

It is not a weakly prime, because it can be changed into another prime (92734805153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 46367402556 + 46367402557.

It is an arithmetic number, because the mean of its divisors is an integer number (46367402557).

Almost surely, 292734805113 is an apocalyptic number.

It is an amenable number.

92734805113 is a deficient number, since it is larger than the sum of its proper divisors (1).

92734805113 is an equidigital number, since it uses as much as digits as its factorization.

92734805113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 181440, while the sum is 43.

The spelling of 92734805113 in words is "ninety-two billion, seven hundred thirty-four million, eight hundred five thousand, one hundred thirteen".