Base | Representation |
---|---|
bin | 101011110101011011… |
… | …0001000101100011011 |
3 | 22222222101102121212201 |
4 | 1113222312020230123 |
5 | 3020241344420042 |
6 | 111124510151031 |
7 | 6541510653403 |
oct | 1275266105433 |
9 | 288871377781 |
10 | 94134373147 |
11 | 36a16443901 |
12 | 162b14b2477 |
13 | 8b52530b19 |
14 | 47b002d803 |
15 | 26ae2e61b7 |
hex | 15ead88b1b |
94134373147 has 2 divisors, whose sum is σ = 94134373148. Its totient is φ = 94134373146.
The previous prime is 94134373121. The next prime is 94134373171. The reversal of 94134373147 is 74137343149.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 94134373147 - 27 = 94134373019 is a prime.
It is a super-2 number, since 2×941343731472 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 94134373097 and 94134373106.
It is not a weakly prime, because it can be changed into another prime (94134373447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 47067186573 + 47067186574.
It is an arithmetic number, because the mean of its divisors is an integer number (47067186574).
Almost surely, 294134373147 is an apocalyptic number.
94134373147 is a deficient number, since it is larger than the sum of its proper divisors (1).
94134373147 is an equidigital number, since it uses as much as digits as its factorization.
94134373147 is an evil number, because the sum of its binary digits is even.
The product of its digits is 762048, while the sum is 46.
The spelling of 94134373147 in words is "ninety-four billion, one hundred thirty-four million, three hundred seventy-three thousand, one hundred forty-seven".
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