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9413890105553 is a prime number
BaseRepresentation
bin1000100011111101011110…
…0100110110000011010001
31020022221220012001200001222
42020333113210312003101
52213214121331334203
632004403103534425
71661062654422653
oct210772744660321
936287805050058
109413890105553
112aaa4545aa3aa
1210805848ba415
135339591108ab
142478c59166d3
15114d2474c038
hex88fd79360d1

9413890105553 has 2 divisors, whose sum is σ = 9413890105554. Its totient is φ = 9413890105552.

The previous prime is 9413890105549. The next prime is 9413890105621. The reversal of 9413890105553 is 3555010983149.

9413890105553 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8790851413969 + 623038691584 = 2964937^2 + 789328^2 .

It is an emirp because it is prime and its reverse (3555010983149) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 9413890105553 - 22 = 9413890105549 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 9413890105495 and 9413890105504.

It is not a weakly prime, because it can be changed into another prime (9413890105513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4706945052776 + 4706945052777.

It is an arithmetic number, because the mean of its divisors is an integer number (4706945052777).

Almost surely, 29413890105553 is an apocalyptic number.

It is an amenable number.

9413890105553 is a deficient number, since it is larger than the sum of its proper divisors (1).

9413890105553 is an equidigital number, since it uses as much as digits as its factorization.

9413890105553 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2916000, while the sum is 53.

The spelling of 9413890105553 in words is "nine trillion, four hundred thirteen billion, eight hundred ninety million, one hundred five thousand, five hundred fifty-three".