94334000113 has 4 divisors (see below), whose sum is σ = 94613923300. Its totient is φ = 94054076928.

The previous prime is 94334000099. The next prime is 94334000147. The reversal of 94334000113 is 31100043349.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 43071606369 + 51262393744 = 207537^2 + 226412^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-94334000113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (94334004113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 139961088 + ... + 139961761.

It is an arithmetic number, because the mean of its divisors is an integer number (23653480825).

Almost surely, 2^94334000113 is an apocalyptic number.

It is an amenable number.

94334000113 is a deficient number, since it is larger than the sum of its proper divisors (279923187).

94334000113 is a wasteful number, since it uses less digits than its factorization.

94334000113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 279923186.

The product of its (nonzero) digits is 3888, while the sum is 28.

The spelling of 94334000113 in words is "ninety-four billion, three hundred thirty-four million, one hundred thirteen", and thus it is an aban number.