Base | Representation |
---|---|
bin | 101100000000001011… |
… | …1101100100001100001 |
3 | 100000220112221101002012 |
4 | 1120000113230201201 |
5 | 3022011321222233 |
6 | 111224410202305 |
7 | 6553454300534 |
oct | 1300027544141 |
9 | 300815841065 |
10 | 94495492193 |
11 | 370912729a3 |
12 | 16392423395 |
13 | 8bac2ab02b |
14 | 4805d92a1b |
15 | 26d0d79548 |
hex | 16005ec861 |
94495492193 has 2 divisors, whose sum is σ = 94495492194. Its totient is φ = 94495492192.
The previous prime is 94495492139. The next prime is 94495492199. The reversal of 94495492193 is 39129459449.
Together with previous prime (94495492139) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 76811013904 + 17684478289 = 277148^2 + 132983^2 .
It is a cyclic number.
It is not a de Polignac number, because 94495492193 - 210 = 94495491169 is a prime.
It is not a weakly prime, because it can be changed into another prime (94495492199) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 47247746096 + 47247746097.
It is an arithmetic number, because the mean of its divisors is an integer number (47247746097).
Almost surely, 294495492193 is an apocalyptic number.
It is an amenable number.
94495492193 is a deficient number, since it is larger than the sum of its proper divisors (1).
94495492193 is an equidigital number, since it uses as much as digits as its factorization.
94495492193 is an evil number, because the sum of its binary digits is even.
The product of its digits is 12597120, while the sum is 59.
The spelling of 94495492193 in words is "ninety-four billion, four hundred ninety-five million, four hundred ninety-two thousand, one hundred ninety-three".
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