95013403 has 2 divisors, whose sum is σ = 95013404. Its totient is φ = 95013402.

The previous prime is 95013389. The next prime is 95013409. The reversal of 95013403 is 30431059.

It is a strong prime.

It is an emirp because it is prime and its reverse (30431059) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 95013403 - 2⁵ = 95013371 is a prime.

It is not a weakly prime, because it can be changed into another prime (95013409) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 47506701 + 47506702.

It is an arithmetic number, because the mean of its divisors is an integer number (47506702).

Almost surely, 2^95013403 is an apocalyptic number.

95013403 is a deficient number, since it is larger than the sum of its proper divisors (1).

95013403 is an equidigital number, since it uses as much as digits as its factorization.

95013403 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1620, while the sum is 25.

The square root of 95013403 is about 9747.4818799524. The cubic root of 95013403 is about 456.3117209802.

The spelling of 95013403 in words is "ninety-five million, thirteen thousand, four hundred three".