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95139982081 is a prime number
BaseRepresentation
bin101100010011011001…
…0001110101100000001
3100002120110122212000001
41120212302032230001
53024321313411311
6111412352000001
76605441335024
oct1304662165401
9302513585001
1095139982081
1137392048771
1216532230001
138c82982cb1
1448677db1bb
15271c7344c1
hex1626c8eb01

95139982081 has 2 divisors, whose sum is σ = 95139982082. Its totient is φ = 95139982080.

The previous prime is 95139982043. The next prime is 95139982087. The reversal of 95139982081 is 18028993159.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 71926412481 + 23213569600 = 268191^2 + 152360^2 .

It is an emirp because it is prime and its reverse (18028993159) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 95139982081 - 221 = 95137884929 is a prime.

It is a super-2 number, since 2×951399820812 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (95139982087) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 47569991040 + 47569991041.

It is an arithmetic number, because the mean of its divisors is an integer number (47569991041).

Almost surely, 295139982081 is an apocalyptic number.

It is an amenable number.

95139982081 is a deficient number, since it is larger than the sum of its proper divisors (1).

95139982081 is an equidigital number, since it uses as much as digits as its factorization.

95139982081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1399680, while the sum is 55.

The spelling of 95139982081 in words is "ninety-five billion, one hundred thirty-nine million, nine hundred eighty-two thousand, eighty-one".