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95408318390993 is a prime number
BaseRepresentation
bin10101101100010111111010…
…111011010010001011010001
3110111210221112202021211002122
4111230113322323102023101
5100001132214002002433
6534525550522224025
726045011033345646
oct2554277273221321
9414727482254078
1095408318390993
1128444493495313
12a84a930955015
134130c72b9cb7a
14197bb042d5dcd
15b06bc8dd5198
hex56c5faed22d1

95408318390993 has 2 divisors, whose sum is σ = 95408318390994. Its totient is φ = 95408318390992.

The previous prime is 95408318390971. The next prime is 95408318390999. The reversal of 95408318390993 is 39909381380459.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 75324225176209 + 20084093214784 = 8678953^2 + 4481528^2 .

It is a cyclic number.

It is not a de Polignac number, because 95408318390993 - 26 = 95408318390929 is a prime.

It is a super-2 number, since 2×954083183909932 (a number of 29 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (95408318390999) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 47704159195496 + 47704159195497.

It is an arithmetic number, because the mean of its divisors is an integer number (47704159195497).

Almost surely, 295408318390993 is an apocalyptic number.

It is an amenable number.

95408318390993 is a deficient number, since it is larger than the sum of its proper divisors (1).

95408318390993 is an equidigital number, since it uses as much as digits as its factorization.

95408318390993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 226748160, while the sum is 71.

The spelling of 95408318390993 in words is "ninety-five trillion, four hundred eight billion, three hundred eighteen million, three hundred ninety thousand, nine hundred ninety-three".