Base | Representation |
---|---|
bin | 10101101101101110001010… |
… | …000011110111011110000011 |
3 | 110112010210112220110000002120 |
4 | 111231232022003313132003 |
5 | 100004141333002033003 |
6 | 535040303025415323 |
7 | 26054466452014413 |
oct | 2555561203673603 |
9 | 415123486400076 |
10 | 95500914096003 |
11 | 2847a78a337a59 |
12 | a864872a9a543 |
13 | 413990b6c0170 |
14 | 19823a9c38643 |
15 | b092e8094853 |
hex | 56db8a0f7783 |
95500914096003 has 32 divisors (see below), whose sum is σ = 137661336207360. Its totient is φ = 58541941054080.
The previous prime is 95500914095971. The next prime is 95500914096019. The reversal of 95500914096003 is 30069041900559.
It is not a de Polignac number, because 95500914096003 - 25 = 95500914095971 is a prime.
It is not an unprimeable number, because it can be changed into a prime (95500914096403) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 65063250 + ... + 66514872.
It is an arithmetic number, because the mean of its divisors is an integer number (4301916756480).
Almost surely, 295500914096003 is an apocalyptic number.
95500914096003 is a deficient number, since it is larger than the sum of its proper divisors (42160422111357).
95500914096003 is a wasteful number, since it uses less digits than its factorization.
95500914096003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1458179.
The product of its (nonzero) digits is 1312200, while the sum is 51.
The spelling of 95500914096003 in words is "ninety-five trillion, five hundred billion, nine hundred fourteen million, ninety-six thousand, three".
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