Search a number
-
+
955637000497 is a prime number
BaseRepresentation
bin11011110100000000110…
…01110110100100110001
310101100122222121112211101
431322000121312210301
5111124121033003442
62011002533244401
7126020401323034
oct15720031664461
93340588545741
10955637000497
1133931319a843
12135260a93701
136c16833978a
143437863301b
1519cd1c03cb7
hexde80676931

955637000497 has 2 divisors, whose sum is σ = 955637000498. Its totient is φ = 955637000496.

The previous prime is 955637000491. The next prime is 955637000537. The reversal of 955637000497 is 794000736559.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 872937044721 + 82699955776 = 934311^2 + 287576^2 .

It is an emirp because it is prime and its reverse (794000736559) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-955637000497 is a prime.

It is not a weakly prime, because it can be changed into another prime (955637000491) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 477818500248 + 477818500249.

It is an arithmetic number, because the mean of its divisors is an integer number (477818500249).

Almost surely, 2955637000497 is an apocalyptic number.

It is an amenable number.

955637000497 is a deficient number, since it is larger than the sum of its proper divisors (1).

955637000497 is an equidigital number, since it uses as much as digits as its factorization.

955637000497 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7144200, while the sum is 55.

The spelling of 955637000497 in words is "nine hundred fifty-five billion, six hundred thirty-seven million, four hundred ninety-seven", and thus it is an aban number.