Base | Representation |
---|---|
bin | 10101110000100100001101… |
… | …111001111111011101010001 |
3 | 110112211111010121221221212112 |
4 | 111300210031321333131101 |
5 | 100020342211301044423 |
6 | 535310152531035105 |
7 | 26104556664432434 |
oct | 2560441571773521 |
9 | 415744117857775 |
10 | 95696399628113 |
11 | 28545684876659 |
12 | a89672a73ba95 |
13 | 415219363b45b |
14 | 198ba3252581b |
15 | b0e43a01da78 |
hex | 57090de7f751 |
95696399628113 has 2 divisors, whose sum is σ = 95696399628114. Its totient is φ = 95696399628112.
The previous prime is 95696399628073. The next prime is 95696399628149. The reversal of 95696399628113 is 31182699369659.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 95694899770129 + 1499857984 = 9782377^2 + 38728^2 .
It is a cyclic number.
It is not a de Polignac number, because 95696399628113 - 224 = 95696382850897 is a prime.
It is not a weakly prime, because it can be changed into another prime (95696399628013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 47848199814056 + 47848199814057.
It is an arithmetic number, because the mean of its divisors is an integer number (47848199814057).
Almost surely, 295696399628113 is an apocalyptic number.
It is an amenable number.
95696399628113 is a deficient number, since it is larger than the sum of its proper divisors (1).
95696399628113 is an equidigital number, since it uses as much as digits as its factorization.
95696399628113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1020366720, while the sum is 77.
The spelling of 95696399628113 in words is "ninety-five trillion, six hundred ninety-six billion, three hundred ninety-nine million, six hundred twenty-eight thousand, one hundred thirteen".
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