95913000473 has 2 divisors, whose sum is σ = 95913000474. Its totient is φ = 95913000472.

The previous prime is 95913000377. The next prime is 95913000517. The reversal of 95913000473 is 37400031959.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 90695538649 + 5217461824 = 301157^2 + 72232^2 .

It is a cyclic number.

It is not a de Polignac number, because 95913000473 - 2¹⁶ = 95912934937 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 95913000473.

It is not a weakly prime, because it can be changed into another prime (95913000773) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 47956500236 + 47956500237.

It is an arithmetic number, because the mean of its divisors is an integer number (47956500237).

Almost surely, 2^95913000473 is an apocalyptic number.

It is an amenable number.

95913000473 is a deficient number, since it is larger than the sum of its proper divisors (1).

95913000473 is an equidigital number, since it uses as much as digits as its factorization.

95913000473 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 102060, while the sum is 41.

The spelling of 95913000473 in words is "ninety-five billion, nine hundred thirteen million, four hundred seventy-three", and thus it is an aban number.