Base | Representation |
---|---|
bin | 1000101110110010101111… |
… | …1111100110100110001011 |
3 | 1020222202020210211211102121 |
4 | 2023230223333212212023 |
5 | 2224241234420000021 |
6 | 32230101410312111 |
7 | 2010401462423635 |
oct | 213545377464613 |
9 | 36882223754377 |
10 | 9599990000011 |
11 | 30713730a1574 |
12 | 10b0661288637 |
13 | 548376728638 |
14 | 2528db8c5a55 |
15 | 119ab7721741 |
hex | 8bb2bfe698b |
9599990000011 has 2 divisors, whose sum is σ = 9599990000012. Its totient is φ = 9599990000010.
The previous prime is 9599989999991. The next prime is 9599990000033. The reversal of 9599990000011 is 1100000999959.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 9599990000011 - 225 = 9599956445579 is a prime.
It is a super-2 number, since 2×95999900000112 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (9599990000911) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4799995000005 + 4799995000006.
It is an arithmetic number, because the mean of its divisors is an integer number (4799995000006).
Almost surely, 29599990000011 is an apocalyptic number.
9599990000011 is a deficient number, since it is larger than the sum of its proper divisors (1).
9599990000011 is an equidigital number, since it uses as much as digits as its factorization.
9599990000011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 295245, while the sum is 52.
The spelling of 9599990000011 in words is "nine trillion, five hundred ninety-nine billion, nine hundred ninety million, eleven", and thus it is an aban number.
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