Base | Representation |
---|---|
bin | 101100101110010011… |
… | …0000001110001110011 |
3 | 100011220101101101002011 |
4 | 1121130212001301303 |
5 | 3033143421100024 |
6 | 112042121303351 |
7 | 6640012634434 |
oct | 1313446016163 |
9 | 304811341064 |
10 | 96042753139 |
11 | 378056a2a53 |
12 | 16744634b57 |
13 | 9097a09a58 |
14 | 491167948b |
15 | 2771b0c094 |
hex | 165c981c73 |
96042753139 has 2 divisors, whose sum is σ = 96042753140. Its totient is φ = 96042753138.
The previous prime is 96042753091. The next prime is 96042753167. The reversal of 96042753139 is 93135724069.
It is a strong prime.
It is an emirp because it is prime and its reverse (93135724069) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 96042753139 - 233 = 87452818547 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 96042753092 and 96042753101.
It is not a weakly prime, because it can be changed into another prime (96042733139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 48021376569 + 48021376570.
It is an arithmetic number, because the mean of its divisors is an integer number (48021376570).
Almost surely, 296042753139 is an apocalyptic number.
96042753139 is a deficient number, since it is larger than the sum of its proper divisors (1).
96042753139 is an equidigital number, since it uses as much as digits as its factorization.
96042753139 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1224720, while the sum is 49.
The spelling of 96042753139 in words is "ninety-six billion, forty-two million, seven hundred fifty-three thousand, one hundred thirty-nine".
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