Base | Representation |
---|---|
bin | 11011111110111010111… |
… | …11011100011011010001 |
3 | 10101220210011001110021001 |
4 | 31333131133130123101 |
5 | 111223114342332031 |
6 | 2013412031102001 |
7 | 126315465504265 |
oct | 15773537343321 |
9 | 3356704043231 |
10 | 961493714641 |
11 | 340849154869 |
12 | 136416371901 |
13 | 6c88c8176c5 |
14 | 347723c40a5 |
15 | 1a025e86861 |
hex | dfdd7dc6d1 |
961493714641 has 2 divisors, whose sum is σ = 961493714642. Its totient is φ = 961493714640.
The previous prime is 961493714537. The next prime is 961493714653. The reversal of 961493714641 is 146417394169.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 957687318225 + 3806396416 = 978615^2 + 61696^2 .
It is a cyclic number.
It is not a de Polignac number, because 961493714641 - 239 = 411737900753 is a prime.
It is not a weakly prime, because it can be changed into another prime (961493711641) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 480746857320 + 480746857321.
It is an arithmetic number, because the mean of its divisors is an integer number (480746857321).
Almost surely, 2961493714641 is an apocalyptic number.
It is an amenable number.
961493714641 is a deficient number, since it is larger than the sum of its proper divisors (1).
961493714641 is an equidigital number, since it uses as much as digits as its factorization.
961493714641 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 3919104, while the sum is 55.
The spelling of 961493714641 in words is "nine hundred sixty-one billion, four hundred ninety-three million, seven hundred fourteen thousand, six hundred forty-one".
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