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9691330300001 = 71384475757143
BaseRepresentation
bin1000110100000111000001…
…0011001100100001100001
31021022111000110201211111022
42031001300103030201201
52232240321024100001
632340045150055225
72020114125235430
oct215016023144141
937274013654438
109691330300001
1130a70853358a9
1211062b2aaa515
13553b72125b1c
142570c47d5117
1511c16159e11b
hex8d0704cc861

9691330300001 has 4 divisors (see below), whose sum is σ = 11075806057152. Its totient is φ = 8306854542852.

The previous prime is 9691330299977. The next prime is 9691330300019. The reversal of 9691330300001 is 1000030331969.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 9691330300001 - 222 = 9691326105697 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (9691330300051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 692237878565 + ... + 692237878578.

It is an arithmetic number, because the mean of its divisors is an integer number (2768951514288).

Almost surely, 29691330300001 is an apocalyptic number.

It is an amenable number.

9691330300001 is a deficient number, since it is larger than the sum of its proper divisors (1384475757151).

9691330300001 is a wasteful number, since it uses less digits than its factorization.

9691330300001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1384475757150.

The product of its (nonzero) digits is 13122, while the sum is 35.

The spelling of 9691330300001 in words is "nine trillion, six hundred ninety-one billion, three hundred thirty million, three hundred thousand, one".

Divisors: 1 7 1384475757143 9691330300001