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9712381918073 = 52311856696983
BaseRepresentation
bin1000110101010101011100…
…0100101111101101111001
31021101111100121001211112112
42031111113010233231321
52233111424232334243
632353450123222105
72021460610110302
oct215252704575571
937344317054475
109712381918073
113104aa843406a
12110a3a9077935
13555b48641673
142581206237a9
1511c9947e5818
hex8d55712fb79

9712381918073 has 4 divisors (see below), whose sum is σ = 9714238620288. Its totient is φ = 9710525215860.

The previous prime is 9712381918049. The next prime is 9712381918087. The reversal of 9712381918073 is 3708191832179.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 9712381918073 - 212 = 9712381913977 is a prime.

It is a super-2 number, since 2×97123819180732 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (9712381918013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 928343261 + ... + 928353722.

It is an arithmetic number, because the mean of its divisors is an integer number (2428559655072).

Almost surely, 29712381918073 is an apocalyptic number.

It is an amenable number.

9712381918073 is a deficient number, since it is larger than the sum of its proper divisors (1856702215).

9712381918073 is a wasteful number, since it uses less digits than its factorization.

9712381918073 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1856702214.

The product of its (nonzero) digits is 4572288, while the sum is 59.

The spelling of 9712381918073 in words is "nine trillion, seven hundred twelve billion, three hundred eighty-one million, nine hundred eighteen thousand, seventy-three".

Divisors: 1 5231 1856696983 9712381918073