Base | Representation |
---|---|
bin | 101101010111111011… |
… | …0010111000111001001 |
3 | 100022111201200200120212 |
4 | 1122233312113013021 |
5 | 3044024010400003 |
6 | 112432455330505 |
7 | 10016433312326 |
oct | 1325766270711 |
9 | 308451620525 |
10 | 97439543753 |
11 | 3836209a462 |
12 | 16a74380a35 |
13 | 925b203786 |
14 | 4a04d93b4d |
15 | 280456add8 |
hex | 16afd971c9 |
97439543753 has 2 divisors, whose sum is σ = 97439543754. Its totient is φ = 97439543752.
The previous prime is 97439543699. The next prime is 97439543767. The reversal of 97439543753 is 35734593479.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 71715233209 + 25724310544 = 267797^2 + 160388^2 .
It is a cyclic number.
It is not a de Polignac number, because 97439543753 - 218 = 97439281609 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 97439543692 and 97439543701.
It is not a weakly prime, because it can be changed into another prime (97439543153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 48719771876 + 48719771877.
It is an arithmetic number, because the mean of its divisors is an integer number (48719771877).
Almost surely, 297439543753 is an apocalyptic number.
It is an amenable number.
97439543753 is a deficient number, since it is larger than the sum of its proper divisors (1).
97439543753 is an equidigital number, since it uses as much as digits as its factorization.
97439543753 is an evil number, because the sum of its binary digits is even.
The product of its digits is 42865200, while the sum is 59.
The spelling of 97439543753 in words is "ninety-seven billion, four hundred thirty-nine million, five hundred forty-three thousand, seven hundred fifty-three".
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