Base | Representation |
---|---|
bin | 101101101010001010… |
… | …1110100110001011011 |
3 | 100101002101201002010222 |
4 | 1123110111310301123 |
5 | 3101302223141413 |
6 | 113013325430255 |
7 | 10040546206661 |
oct | 1332425646133 |
9 | 311071632128 |
10 | 98051771483 |
11 | 3864673a196 |
12 | 1700540b38b |
13 | 9327cc0bc3 |
14 | 4a62400c31 |
15 | 283d1a1b08 |
hex | 16d4574c5b |
98051771483 has 2 divisors, whose sum is σ = 98051771484. Its totient is φ = 98051771482.
The previous prime is 98051771413. The next prime is 98051771561. The reversal of 98051771483 is 38417715089.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 98051771483 - 234 = 80871902299 is a prime.
It is a super-3 number, since 3×980517714833 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (98051771413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49025885741 + 49025885742.
It is an arithmetic number, because the mean of its divisors is an integer number (49025885742).
Almost surely, 298051771483 is an apocalyptic number.
98051771483 is a deficient number, since it is larger than the sum of its proper divisors (1).
98051771483 is an equidigital number, since it uses as much as digits as its factorization.
98051771483 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1693440, while the sum is 53.
The spelling of 98051771483 in words is "ninety-eight billion, fifty-one million, seven hundred seventy-one thousand, four hundred eighty-three".
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