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9811382328017 is a prime number
BaseRepresentation
bin1000111011000110001111…
…1101010101101011010001
31021201221220002210202000022
42032301203331111223101
52241222202333444032
632511141541433225
72031564125523134
oct216614375255321
937657802722008
109811382328017
113142a905a6386
12112561810b815
135622950286aa
1425cc32a0221b
1512033add0512
hex8ec63f55ad1

9811382328017 has 2 divisors, whose sum is σ = 9811382328018. Its totient is φ = 9811382328016.

The previous prime is 9811382327993. The next prime is 9811382328023. The reversal of 9811382328017 is 7108232831189.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5670499200961 + 4140883127056 = 2381281^2 + 2034916^2 .

It is a cyclic number.

It is not a de Polignac number, because 9811382328017 - 216 = 9811382262481 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 9811382328017.

It is not a weakly prime, because it can be changed into another prime (9811382324017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4905691164008 + 4905691164009.

It is an arithmetic number, because the mean of its divisors is an integer number (4905691164009).

Almost surely, 29811382328017 is an apocalyptic number.

It is an amenable number.

9811382328017 is a deficient number, since it is larger than the sum of its proper divisors (1).

9811382328017 is an equidigital number, since it uses as much as digits as its factorization.

9811382328017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1161216, while the sum is 53.

The spelling of 9811382328017 in words is "nine trillion, eight hundred eleven billion, three hundred eighty-two million, three hundred twenty-eight thousand, seventeen".