Base | Representation |
---|---|
bin | 1000111011001101100001… |
… | …0110001100101111000001 |
3 | 1021202010221012002212012202 |
4 | 2032303120112030233001 |
5 | 2241240202230031144 |
6 | 32512103414202545 |
7 | 2031663406135265 |
oct | 216633026145701 |
9 | 37663835085182 |
10 | 9813335002049 |
11 | 31438a2859277 |
12 | 1125a82053455 |
13 | 562516742807 |
14 | 25cd7a09c0a5 |
15 | 12040254564e |
hex | 8ecd858cbc1 |
9813335002049 has 2 divisors, whose sum is σ = 9813335002050. Its totient is φ = 9813335002048.
The previous prime is 9813335002001. The next prime is 9813335002231. The reversal of 9813335002049 is 9402005333189.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6702584434225 + 3110750567824 = 2588935^2 + 1763732^2 .
It is a cyclic number.
It is not a de Polignac number, because 9813335002049 - 240 = 8713823374273 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 9813335001994 and 9813335002012.
It is not a weakly prime, because it can be changed into another prime (9813335002249) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4906667501024 + 4906667501025.
It is an arithmetic number, because the mean of its divisors is an integer number (4906667501025).
Almost surely, 29813335002049 is an apocalyptic number.
It is an amenable number.
9813335002049 is a deficient number, since it is larger than the sum of its proper divisors (1).
9813335002049 is an equidigital number, since it uses as much as digits as its factorization.
9813335002049 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 699840, while the sum is 47.
The spelling of 9813335002049 in words is "nine trillion, eight hundred thirteen billion, three hundred thirty-five million, two thousand, forty-nine".
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