981411000953 has 2 divisors, whose sum is σ = 981411000954. Its totient is φ = 981411000952.

The previous prime is 981411000923. The next prime is 981411000961. The reversal of 981411000953 is 359000114189.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 770204577769 + 211206423184 = 877613^2 + 459572^2 .

It is a cyclic number.

It is not a de Polignac number, because 981411000953 - 2¹⁸ = 981410738809 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 981411000953.

It is not a weakly prime, because it can be changed into another prime (981411000923) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 490705500476 + 490705500477.

It is an arithmetic number, because the mean of its divisors is an integer number (490705500477).

Almost surely, 2^981411000953 is an apocalyptic number.

It is an amenable number.

981411000953 is a deficient number, since it is larger than the sum of its proper divisors (1).

981411000953 is an equidigital number, since it uses as much as digits as its factorization.

981411000953 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 38880, while the sum is 41.

The spelling of 981411000953 in words is "nine hundred eighty-one billion, four hundred eleven million, nine hundred fifty-three", and thus it is an aban number.