Base | Representation |
---|---|
bin | 101101111001001001… |
… | …0110111000111001001 |
3 | 100102101102022201220212 |
4 | 1123302102313013021 |
5 | 3103314400423423 |
6 | 113135240530505 |
7 | 10056160552046 |
oct | 1336222670711 |
9 | 312342281825 |
10 | 98554311113 |
11 | 388843806a5 |
12 | 17125780a35 |
13 | 93a8154c2b |
14 | 4aad0581cd |
15 | 286c36c578 |
hex | 16f24b71c9 |
98554311113 has 2 divisors, whose sum is σ = 98554311114. Its totient is φ = 98554311112.
The previous prime is 98554311061. The next prime is 98554311131. The reversal of 98554311113 is 31111345589.
Together with next prime (98554311131) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 87590545849 + 10963765264 = 295957^2 + 104708^2 .
It is a cyclic number.
It is not a de Polignac number, because 98554311113 - 218 = 98554048969 is a prime.
It is not a weakly prime, because it can be changed into another prime (98554311143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49277155556 + 49277155557.
It is an arithmetic number, because the mean of its divisors is an integer number (49277155557).
Almost surely, 298554311113 is an apocalyptic number.
It is an amenable number.
98554311113 is a deficient number, since it is larger than the sum of its proper divisors (1).
98554311113 is an equidigital number, since it uses as much as digits as its factorization.
98554311113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 64800, while the sum is 41.
The spelling of 98554311113 in words is "ninety-eight billion, five hundred fifty-four million, three hundred eleven thousand, one hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •