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9881422501673 is a prime number
BaseRepresentation
bin1000111111001011001010…
…1011011001011100101001
31021222122200022202012210002
42033302302223121130221
52243344123130023143
633003243545432345
72036623601263142
oct217626253313451
937878608665702
109881422501673
11316a762437518
12113710449b6b5
13568a7789a928
14262398ab4ac9
15122089cc95b8
hex8fcb2ad9729

9881422501673 has 2 divisors, whose sum is σ = 9881422501674. Its totient is φ = 9881422501672.

The previous prime is 9881422501661. The next prime is 9881422501787. The reversal of 9881422501673 is 3761052241889.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8573722760464 + 1307699741209 = 2928092^2 + 1143547^2 .

It is a cyclic number.

It is not a de Polignac number, because 9881422501673 - 26 = 9881422501609 is a prime.

It is not a weakly prime, because it can be changed into another prime (9881421501673) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4940711250836 + 4940711250837.

It is an arithmetic number, because the mean of its divisors is an integer number (4940711250837).

It is a 2-persistent number, because it is pandigital, and so is 2⋅9881422501673 = 19762845003346, but 3⋅9881422501673 = 29644267505019 is not.

Almost surely, 29881422501673 is an apocalyptic number.

It is an amenable number.

9881422501673 is a deficient number, since it is larger than the sum of its proper divisors (1).

9881422501673 is an equidigital number, since it uses as much as digits as its factorization.

9881422501673 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5806080, while the sum is 56.

Adding to 9881422501673 its sum of digits (56), we get a square (9881422501729 = 31434732).

The spelling of 9881422501673 in words is "nine trillion, eight hundred eighty-one billion, four hundred twenty-two million, five hundred one thousand, six hundred seventy-three".