Base | Representation |
---|---|
bin | 11100110100000001010… |
… | …10000100011100000001 |
3 | 10111122100212112002022121 |
4 | 32122000222010130001 |
5 | 112210010223134303 |
6 | 2034444501004241 |
7 | 131345101366153 |
oct | 16320052043401 |
9 | 3448325462277 |
10 | 990000989953 |
11 | 351947827728 |
12 | 13ba513b3681 |
13 | 72483866b51 |
14 | 35cb84a0ad3 |
15 | 1ab43a019bd |
hex | e680a84701 |
990000989953 has 2 divisors, whose sum is σ = 990000989954. Its totient is φ = 990000989952.
The previous prime is 990000989947. The next prime is 990000990037. The reversal of 990000989953 is 359989000099.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 647434264689 + 342566725264 = 804633^2 + 585292^2 .
It is a cyclic number.
It is not a de Polignac number, because 990000989953 - 29 = 990000989441 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 990000989891 and 990000989900.
It is not a weakly prime, because it can be changed into another prime (990000389953) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 495000494976 + 495000494977.
It is an arithmetic number, because the mean of its divisors is an integer number (495000494977).
Almost surely, 2990000989953 is an apocalyptic number.
It is an amenable number.
990000989953 is a deficient number, since it is larger than the sum of its proper divisors (1).
990000989953 is an equidigital number, since it uses as much as digits as its factorization.
990000989953 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7085880, while the sum is 61.
The spelling of 990000989953 in words is "nine hundred ninety billion, nine hundred eighty-nine thousand, nine hundred fifty-three".
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