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99000099000193 is a prime number
BaseRepresentation
bin10110100000101001000001…
…101110111100111110000001
3110222112022120010011211112111
4112200221001232330332001
5100434004200321001233
6550320003450055321
726565343512652426
oct2640510156747601
9428468503154474
1099000099000193
11295a9784a5a626
12b12aa70a1a541
134331891530b01
141a638b79b9d4d
15b6a346ab1acd
hex5a0a41bbcf81

99000099000193 has 2 divisors, whose sum is σ = 99000099000194. Its totient is φ = 99000099000192.

The previous prime is 99000099000079. The next prime is 99000099000199. The reversal of 99000099000193 is 39100099000099.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 94431205575184 + 4568893425009 = 9717572^2 + 2137497^2 .

It is a cyclic number.

It is not a de Polignac number, because 99000099000193 - 221 = 99000096903041 is a prime.

It is not a weakly prime, because it can be changed into another prime (99000099000199) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49500049500096 + 49500049500097.

It is an arithmetic number, because the mean of its divisors is an integer number (49500049500097).

Almost surely, 299000099000193 is an apocalyptic number.

It is an amenable number.

99000099000193 is a deficient number, since it is larger than the sum of its proper divisors (1).

99000099000193 is an equidigital number, since it uses as much as digits as its factorization.

99000099000193 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 177147, while the sum is 49.

The spelling of 99000099000193 in words is "ninety-nine trillion, ninety-nine million, one hundred ninety-three", and thus it is an aban number.