Base | Representation |
---|---|
bin | 10110100000101001000001… |
… | …101110111100111110000001 |
3 | 110222112022120010011211112111 |
4 | 112200221001232330332001 |
5 | 100434004200321001233 |
6 | 550320003450055321 |
7 | 26565343512652426 |
oct | 2640510156747601 |
9 | 428468503154474 |
10 | 99000099000193 |
11 | 295a9784a5a626 |
12 | b12aa70a1a541 |
13 | 4331891530b01 |
14 | 1a638b79b9d4d |
15 | b6a346ab1acd |
hex | 5a0a41bbcf81 |
99000099000193 has 2 divisors, whose sum is σ = 99000099000194. Its totient is φ = 99000099000192.
The previous prime is 99000099000079. The next prime is 99000099000199. The reversal of 99000099000193 is 39100099000099.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 94431205575184 + 4568893425009 = 9717572^2 + 2137497^2 .
It is a cyclic number.
It is not a de Polignac number, because 99000099000193 - 221 = 99000096903041 is a prime.
It is not a weakly prime, because it can be changed into another prime (99000099000199) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49500049500096 + 49500049500097.
It is an arithmetic number, because the mean of its divisors is an integer number (49500049500097).
Almost surely, 299000099000193 is an apocalyptic number.
It is an amenable number.
99000099000193 is a deficient number, since it is larger than the sum of its proper divisors (1).
99000099000193 is an equidigital number, since it uses as much as digits as its factorization.
99000099000193 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 177147, while the sum is 49.
The spelling of 99000099000193 in words is "ninety-nine trillion, ninety-nine million, one hundred ninety-three", and thus it is an aban number.
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