9900025433 has 4 divisors (see below), whose sum is σ = 10110664320. Its totient is φ = 9689386548.

The previous prime is 9900025427. The next prime is 9900025477. The reversal of 9900025433 is 3345200099.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 9900025433 - 2⁴ = 9900025417 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 9900025393 and 9900025402.

It is not an unprimeable number, because it can be changed into a prime (9900075433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 105319373 + ... + 105319466.

It is an arithmetic number, because the mean of its divisors is an integer number (2527666080).

Almost surely, 2^9900025433 is an apocalyptic number.

It is an amenable number.

9900025433 is a deficient number, since it is larger than the sum of its proper divisors (210638887).

9900025433 is a wasteful number, since it uses less digits than its factorization.

9900025433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 210638886.

The product of its (nonzero) digits is 29160, while the sum is 35.

The square root of 9900025433 is about 99498.8715162137. The cubic root of 9900025433 is about 2147.2310077540.

The spelling of 9900025433 in words is "nine billion, nine hundred million, twenty-five thousand, four hundred thirty-three".